Touch.position VS Touch.rawPosition

Hey guys,

What I want to do is detect how far they have dragged their finger across the screen. So I just need to calculate the distance between the position where they first touched the screen and the position where they lifted their finger.

From what I have read in the docs it looks like Touch.rawPosition will tell me where they first touched the screen :

However, when I print out the contents of rawPostion, namely the X value :

Code (CSharp):

1. Debug.Log(myTouch.rawPosition.x)

It displays a value of 9.416726E-43 regardless of where I touch the screen.

Obviously on Touch.BEGAN I could just save the Touch.position to a vector and use that, but if could use this rawPosition that would save me from creating a variable.

Any idea what I am doing wrong?

Thanks!

 

I’m having this exact issue on Unity 2020.3.8f1 while simulating Apple iPhone 12 Pro using the device simulator preview package on Windows. Touch.position works fine, gives position in screen space convertible to world space. Touch.rawPosition however gives ~6E-43 and ~6E+10 for x and y values respectively.

 

I'm having the same problem except when i convert to world space, it consistently comes up as (-4.8, -6.4) which is literally the bottom left hand corner of my screen.

According to the documentation this means it is returning (0, 0) every time (my screen is 960px by 1280px with the origin being the center of the screen and 100px per world unit):

Unity Scripting API: The bottom-left of the screen or window is at (0, 0). The top-right of the screen or window is at (Screen.width, Screen.height).

 

Anyone got anything on this? I'm looking at touch.rawposition now, Unity 2021.2.10f1, using the simulator. Touches always have rawposition (0,0)

 

same, Unity 2021.3.16

 

Same... Unity 2023.1.16
Touch.rawPosition always returns 0,0 wherever I click the simulated screen.