Resolved Testing a left mouse button down at a certain position

Hi,

I'm currently writing a Unit Test where I have this action:




It's just a Vector2Control with a Composite with One Modifier, where the Modifier is the left mouse button and the binding is the mouse position.

Then, I've the following test for that:

Code (CSharp):

1. public class InputReaderSOTests : InputTestFixture
2. {
3.   [Test]
4.   public void DoesExecuteClickEventWhenEnabled()
5.   {
6.     var mouse = InputSystem.AddDevice<Mouse>();
7.      
8.     var inputReader = ScriptableObject.CreateInstance<InputReaderSO>();
9.     inputReader.EnablePlayerControls();
10.  
11.     var clickedVector = Vector2.zero;
12.     inputReader.Click += position => clickedVector = position;
13.      
14.     // Works
15.     /*InputSystem.QueueStateEvent(mouse, new MouseState() { position = new Vector2(1337, 1337)}.WithButton(MouseButton.Left ));
16.     InputSystem.Update();*/
17.      
18.     // Does not work
19.     /*Set(mouse.position, new Vector2(1337, 1337), queueEventOnly: false);
20.     Click(mouse.leftButton);*/
21.      
22.     clickedVector.Should().Be(new Vector2(1337, 1337));
23.   }
24. }

In the documentation there's a entry about using Set/Click/Press etc. for setting the state.

As you can see in the example, I set the mouse.position and then I click the left mouse button. However, the test reports that the mouse was not clicked on that position.

However, if I use the other method above using InputSystem.QueueStateEvent and InputSystem.Update it works as expected.

I feel that it also should work with set Set and Click methods. Any idea what I'm missing?

Thanks!

 

Dang. Some minutes later I found it.

Instead of using Set, I have to use Move:

Code (CSharp):

1. Move(mouse.position, new Vector2(1337, 1337), queueEventOnly: true);
2. Click(mouse.leftButton);

Then it works as expected, nice!

 

are you using this in a EditTest? How to move a mouse without Screen?