Slant Physics Raycast Implementation

For my 3d car game, I was doing Physics raycast to detect obstacles and based on detect take turn left or right side. Currently, I was doing straight raycast and I can't able to detect left and right side existed obstacles.

So I decided to do little bit slant raycast to detect something from the left and right side.
The following image explains a better way my question:



This code is running at present:

Code (CSharp):

1.  Ray rayRight = new Ray(thisTransform.position + Vector3.up * 0.2f + thisTransform.right * detectAngle * 0.5f + transform.right * detectAngle * 0.0f * Mathf.Sin(Time.time * 50), transform.TransformDirection(Vector3.forward) * detectDistance);
2.         Ray rayLeft = new Ray(thisTransform.position + Vector3.up * 0.2f + thisTransform.right * -detectAngle * 0.5f - transform.right * detectAngle * 0.0f * Mathf.Sin(Time.time * 50), transform.TransformDirection(Vector3.forward) * detectDistance);
3.  
4.         Debug.DrawRay(rayRight.origin, rayRight.direction * detectDistance, Color.red);
5.         Debug.DrawRay(rayLeft.origin, rayLeft.direction * detectDistance, Color.red);

Now please give me a guidance to do slant physics raycast to detect obstacles.

 

First up, in the ray constructor, you don't need

transform.TransformDirection(Vector3.forward)

. You can just use

transform.forward

instead.

For a simple way to add a bit of an angle, you could add the side direction:

Code (CSharp):

1. Vector3 rayVector = thisTransform.forward + (thisTransform.right * 0.5f);
2. rayVector *= detectDistance / rayVector.magnitude;

The amount you multiply the right vector by dictates the angle. If you want precise control, multiplied by 1 is 45 degrees. Multiplied by another value you can use trig to work it out: the multiplier is tan of the angle from forwards

tan angle = opposite (multiplier) / adjacent (1)