Random Position (Based On Screen Size)

Hello!! I have a simple game where you try and tap a target. When you succeed the target will randomly pick a new position on the screen and move their > and the process repeats. My problem is I don't know how to code it to where it never appears outside the bounds of the parent RectTransform area.

Is there even a way to do this?? Here's what I have so far: But it doesn't account for any changes in screen size. So while -160/160x, and -270/270y are the maximum positions of the a phone size, if I move to an ipad screen size it only picks position within a small part of the screen

https://ibb.co/XCnQ5tP

Code (CSharp):

1. using System.Collections;
2. using System.Collections.Generic;
3. using UnityEngine;
4. using UnityEngine.UI;
5.  
6. public class ButtonControls : MonoBehaviour
7. {
8.     public RectTransform myRect;
9.  
10.     public void WasClicked()
11.     {
12.         myRect.transform.localPosition = new Vector3(Random.Range(-160,160), Random.Range(-270,270), 0);
13.     }
14. }

Thank you for your time!

 

You can get the current screen resolution:
https://docs.unity3d.com/ScriptReference/Screen-currentResolution.html
And then place your object at a random point within these width and height values minus half the objects' size.

 

Thank you! That worked!!!!