Mathf.Pow return wrong value??

Hi guys,
I'm try use Mathf.Pow method but maybe I don't know how it's realy work...
Let's go, it's my debug code:

Code (CSharp):

1.  Debug.Log ("Acceleration Y:  " + Input.acceleration.y + "  Result:  " + Mathf.Pow(Input.acceleration.y, 0) + "\nAccelerationX:  " + Input.acceleration.x + "  Result:  " + Mathf.Pow(Input.acceleration.x , 0));
2.  

Ok, it's will get acceleration value and power of 0, right?
So, assuming than Y value is -0.875, -0.875 to the power of 0 is -1, but the unity return 1! why??
I'm forgetting something ??
Look this real output:

Code (CSharp):

1. Acceleration Y:  -0.2080078  Result:  1
2. Acceleration X:  -0.08300781  Result:  1

Unity return 1 but it's should be -1.
look this one:

Code (CSharp):

1. Acceleration Y:  0.01171875  Result:  1
2. Acceleration X:  0.1259766  Result:  1

This one is right, it's only work with positive number or I'm crazy? :/

 

Looks like you're just overlooking math: anything to the zero power is 1, even negative numbers.

 

Are you sure?
Look:

 

Look carefully at the brackets in your screenshot.

 

Wow, I made a miss...
Seemingly I ignore it, for make this in Google and my smartphone calculator is need a brackets in negative sign, such as (-3) ^ 0, and in unity not.
Sory for it, I am very embarrassed.

 

As an alternative, maybe this is what you're looking for.
http://docs.unity3d.com/ScriptReference/Mathf.Sign.html

 

Yes, is it! Thank you!