Mathf.PerlinNoise() a way to random seed it?

I find this function great and fast but there does not appear to be a way to set it so that it can be re-seeded with a new random noise set?

Is this a missing feature or have I missed an indirect way to re-seed Mathf.PerlinNoise()?

 

its not built in but you can

Code (csharp):

1. int newNoise = Random.Range(0,10000);
2.  
3. something = Mathf.PerlinNoise(x + newNoise, z + newNoise);

there are a lot of "better" noise function for free on the internet.
I use SimplexNoise usually.

 

There is no need to reseed Mathf.PerlinNoise() because it is virtually endless. Just pick a new random location to get values from.

 

That would be seeding though, he is just looking for a way to make it so you don't produce the same numbers every time, and that would be how you do it.

 

Code (CSharp):

1. float Perlin(float x, float y)
2. {
3.         for(x; x< ChunkSize; x++)
4.        {
5.                 for(y; y < ChunkSize; y++)
6.                 {
7.                         return Mathf.PerlinNoise(x,y);
8.                  }
9.          }
10. }

Something like that. reseed in chunks.
OORRRRR just use Input.GetKeyUp(KeyCode.E) to reseed with the E key.

Code (CSharp):

1. void Update()
2. {
3.  if (Input.GetKeyUp(KeyCode.E)) {
4.   Mathf.PerlinNoise(x,y);
5.  }
6. }