Question How to get layout of VisualElement via script?

so my element looks like this, and I need to somehow get the layout of each child of #Container element

My script looks like this

Code (CSharp):

1.  
2. public VisualTreeAsset visualTreeAsset;
3.     public VisualElement visualElement;
4.  
5.     void Start()
6.     {
7.         VisualElement rootElement = visualTreeAsset.CloneTree();
8.  
9.         var panel = rootElement.Q<VisualElement>("Container");
10.  
11.         foreach (var blockElement in panel.Children())
12.         {
13.           Debug.Log("X: " + blockElement.layout.x + ", " + "Y: " + blockElement.layout.y);
14.         }
15.     }
16.  

but as a result I get this


What am I doing wrong? Help please

 

Be sure to print out an identifier for each element, ideally the name or "hashtag", so you know what kind of element you are printing this info for.

It's probably easiest to just set a breakpoint on the Debug line. Then inspect the blockElement in the IDE to find the property you are looking for.

I know I always got confused because at runtime you have to go through the style property to get desired style settings, not the root.

But ... I think the issue is different here. Perhaps you need to log this at a later time because in Start the visual tree may not have performed any layouting yet thus all layout values are still uninitialized (0). Try logging in LateUpdate to verify that assumption.