How to get 4 random numbers in a row, without them being the same.

I have a quiz game and i need to randomize the button texts, i need some kind of way get 4 numbers between 0 and 3 in randomized order.
LippuScript.Lista is a list from other script witch has 3 random answers and one correct answer.
The problem i am having is that the correct answer is always at the same spot.

Code (CSharp):

1.  
2.        
3.         randomilistasta = lippuScript.Lista[0];
4.         randomilistasta2 = lippuScript.Lista[1];
5.         randomilistasta3 = lippuScript.Lista[2];
6.         randomilistastaVika = lippuScript.Lista[3];
7.  
8.         Button1.text = randomilistasta;
9.         Button2.text = randomilistasta2;
10.         Button3.text = randomilistasta3;
11.         Button4.text = randomilistastaVika;

 

There are many many ways to shuffle a list in c#. As you have only 4 items and performance/garbage isn't an issue, try with Linq:

Code (CSharp):

1. using System.Linq;
2.  
3. void SomeMethod()
4. {
5.     var shuffledList = lippuScript.Lista.OrderBy(a => System.Guid.NewGuid()).ToList();
6.  
7.     Button1.text = shuffledList[0];
8.     Button2.text = shuffledList[1];
9.     Button3.text = shuffledList[2];
10.     Button4.text = shuffledList[3];
11. }

Of course, be sure that your list has those 4 items or you'll get exceptions

 

Thank you very much!

 

Shuffle and pick!

https://gist.github.com/kurtdekker/6f9c33ad653d0feac22838225ba21c6c