Have multiple enemies keep distance from one another

Hi guys,

so I'm trying to have a group of enemies maintain distance from one another,until one is given permission to fight the player. I also want them to 'circle' around the player, while waiting for their turn. Think old dubbed action movies.

 

Put them on a circle around the player, and space them evenly by Phi (divide 2*Pi by the number of enemies). If you NNeed to have minimal Separation between the enemies, from one to the next, remember that the distance to the next Player is almost equal to distance = sin(Phi) * radius, and solve for radius

Edit:
I got that wrong: the mindistance between Players c = 2*radius * sin(phi/2). Solve for radius.

 

So how to put them in a circle, in this implementation? clampmagnitude?
seperation isnt an issue, if i have 3 enemies, they can all be evenly spaced around the player.

so my code would be

Distance = sin( 2* Pi/numEnemies) * radius;

where radius is how far away i want them? How to get this as a vector/location

 

im still a little lost how to get the object to here, as a location from the player, tbh.

should i not be able to set the radius as a variable of my choice?

or am i thinking about this backwards?

 

For a point on a circle:
https://math.stackexchange.com/questions/260096/find-the-coordinates-of-a-point-on-a-circle
if you have 3 enemies then your theta will be 360 / 3 and so on..
I think the final formula of theta will be

Code (CSharp):

1.  
2. var theta = 0f;
3. offset += Time.deltatime * speed; // if you want to move the enemies
4. for (int i = 0; i < NumberOfEnemies; i++)
5. {
6.   theta += offset + (360 / NumberOfEnemies) * (i + 1);//later edit
7.   //here place your enemy with formula from link
8. }

 

The distance between the enemies (when spaced around a circle evenly by the same angle) is defined by the radius. Think about spokes in a wheel. If you need more distance between the spokes, you'll have to out further (increase the radius) until the are fare enough apart.

 

okay cool thanks, this does make sense now. i was thinking about this backwards.