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Question Getting rectangle of grid cells between to coordinates

Discussion in 'Scripting' started by Jugro, Nov 17, 2022.

  1. Jugro

    Jugro

    Joined:
    Nov 7, 2022
    Posts:
    1
    Hey guys,

    I'm kinda stuck with finding all cells of a grid between two coordinates.
    I've come to a point where I can select a line from a to b using a lerp like that:



    But what I really want is selecting all grid cells between the vectors in a rectangle:




    Can someone point me in the right direction? I fell like spending hours but the most I can do is some bad hacks which work more or less.

    Thank you!
     
    Jugro, Nov 17, 2022
    #1

  2. MelvMay

    MelvMay

    Unity Technologies

    Joined:
    May 24, 2013
    Posts:
    10,620
    What does "selecting" mean? If you only want the X and Y and not use a Vector2Int then I'm not sure what the confusion is.

    X goes from startPosition.x to endPosition.x and Y goes from startPosition.y to endPosition.y
     
    MelvMay, Nov 17, 2022
    #2

  3. MelvMay

    MelvMay

    Unity Technologies

    Joined:
    May 24, 2013
    Posts:
    10,620
    Maybe you mean something like this:
    Code (CSharp):
    1. // Find the min/max.
    2. var min = Vector3Int.Min(startPosition, endPosition);
    3. var max = Vector3Int.Max(startPosition, endPosition);
    4.  
    5. // Iterate them all.
    6. for(var x = min.x; x < max.x; ++x)
    7. {
    8.    for(var y = min.y; x < max.y; ++y)
    9.    {
    10.        // Do something.      
    11.    }
    12. }
     
    MelvMay, Nov 17, 2022
    #3
    AnimalMan likes this.

  4. NFinfinity

    NFinfinity

    Joined:
    Aug 2, 2021
    Posts:
    2
    A note to anyone who finds this later: I think the code above has an infinite loop in the 8th line. Var y (not X)should be less than max.y, otherwise the second loop will never reach max.y.

    for(var y = min.y; y < max.y; ++y)

    1. // Find the min/max.
    2. var min = Vector3Int.Min(startPosition, endPosition);
    3. var max = Vector3Int.Max(startPosition, endPosition);

    5. // Iterate them all.
    6. for(var x = min.x; x < max.x; ++x)
    7. {
    8. for(var y = min.y; x < max.y; ++y)
    9. {
    10. // Do something.
    11. }
    12. }
     
    NFinfinity, Aug 27, 2023
    #4